Find the value of c in rolle's theorem for the function f(x)=x^3-3x
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Answer:
(+/-) 1
Step-by-step explanation:
f(x) is a polynomial function & therefore it's differentiable
now...a/c to Rolle's theorem, there exists a 'c' in R for which f'(c) = 0
f(x) = x^3 - 3x
f'(x) = 3x^2 - 3
f'(c) = 3c^2 - 3 = 0
hence...c = (+/-) 1
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