find the value of c so that the polynomial 2x^3-7x^2-x+c is exactly divided by x+3/2
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ANSWER:
Given:
- p(x) = 2x³ - 7x² - x + c
To Find:
- Value of c so that p(x) is exactly divisible by (x + 3/2)
Solution:
We are given that,
⇒ p(x) = 2x³ - 7x² - x + c
We need to find the value of c, for which p(x) is perfectly divisible by (x + 3/2).
So, that means p(3/2) is 0.
⇒ p(x) = 2x³ - 7x² - x + c
⇒ p(3/2) = 2(3/2)³ - 7(3/2)² - (3/2) + c
⇒ 0 = 2(27/8) - 7(9/4) - 3/2 + c
Simplifying the terms,
⇒ 27/4 - 63/4 - 3/2 + c = 0
Taking LCM,
⇒ (27 - 63 - 6 + 4c)/4 = 0
Transposing 4 to RHS,
⇒ 27 - 63 - 6 + 4c = 0
⇒ -42 + 4c = 0
Transposing 42 to RHS,
⇒ 4c = 42
Transposing 4 to RHS,
⇒ c = 42/4
Simplifying the terms,
⇒ c = 21/2
Therefore, the value of c for which p(x) is completely divisible by (x + 3/2) is 21/2.
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