Question

Find the value of c that makes t2−22t+c a perfect square trinomial.

Answer 1

Answer:

c is equal to 121.

Step-by-step explanation:

I don't know if I am correct. But answering this.

Given polynomial is t2−22t+c

let's make this into (a-b)^2 form

t2 -2*11*t + c = (t - √c)^2 = t2 - 2*√c *t + c

so from here we can say

√c = 11

or c = 121.

Hope you are satisfied with the solution.