Question

Find the value of constant a and b for which sinx cosx (5 tanx + 2 cotx ) = a+b sin squarex

Answer 1

sin x.cosx(5tan x + 2cot x) = sinx.cosx(5sinx/cos x + 2cos x/sin x) = 5sin^2 x + 2cos^2 x = 5sin^2 x + 2(1-sin^2 x) = 3sin^2 x + 2.Now, comparing it with the form a+bsin^2 x , we get: a = 2 and b = 3.

Answer 2

Answer:

a=2 and b= 3 see above

Step-by-step explanation:

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