Math, asked by JobanJosan11, 11 months ago

Find the value of constant.

i) 8kx(x-1)+1=0

Answers

Answered by hancyamit2003

1

Answer:

8Kx(x-1)+1=0

8Kx(x-1)= -1

Kx(x-1)= -1/8

K= -1/8(x^2-x)

Step-by-step explanation:

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