Math, asked by vepamakulavenkatacha, 11 months ago

Find the value of cos 0 + sin 90 + root 2 + cot 45 + tan 45 + cos 90

Answers

Answered by asmisona1
1

Answer:

1+1+root2+1+1+0

4+root2

Answered by SaurabhJacob
0

The value of cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90° is 4 + √2.

Given,

cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90°

To Find,

The value of cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90°.

Solution,

We know that,

cos 0° = 1, sin 90° = 1, cot 45° = 1, tan 45° = 1, and cos 90° = 0.

Adding all the above values, we get,

⇒cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90° = 1 + 1 + √2 + 1 + 1 + 0

                                                                                       = 4 + √2

Therefore, the value of cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90° is 4 + √2.

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