Find the value of cos 0 + sin 90 + root 2 + cot 45 + tan 45 + cos 90
Answers
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1
Answer:
1+1+root2+1+1+0
4+root2
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The value of cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90° is 4 + √2.
Given,
cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90°
To Find,
The value of cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90°.
Solution,
We know that,
cos 0° = 1, sin 90° = 1, cot 45° = 1, tan 45° = 1, and cos 90° = 0.
Adding all the above values, we get,
⇒cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90° = 1 + 1 + √2 + 1 + 1 + 0
= 4 + √2
Therefore, the value of cos 0° + sin 90° + √2 + cot 45° + tan 45° + cos 90° is 4 + √2.
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