Find the value of
(cos 0° + sin 45°+ sin 30°) (sin 90° – cos 45° + cos 60°)
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Answered by
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Answer:
Explanation:
Cos 0 =1 etc
Putting in their values , we get,
(1+1/√2 + 1/2)(1-1√2+1/2) l. C. M:
(2+√2 + 1)whole divided by 2 (2-√2+1) whole by 2
(3+√2)/2 (3-√2)/2
(9-2)/4. (A square - b square = (a-b) (a+b)
7/4
1.75
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