Question

Find the value of cos 0° + sin 90° + root 2 sin 45° + cot 45° + tan 45º + cos90°.​

Answer 1

Answer:

$\cos(0) + \sin(90) + \sqrt{2} \sin(45) + \cot(45) + \tan(45) + \cos(90)$

$= > 1 + 1 + \sqrt{2} \times \frac{1}{ \sqrt{2} } + 1 + 1 + 0 \\ = > 2 + 1 + 1 + 1 + 0 \\ = > 5$

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Answer 2

Answer:

The value of the equation is 5

Step-by-step explanation:

• Trigonometric angles are the angles given by the trigonometric function.
• Example: Sin, cos, tan
• The angles can give the relationship between the sides of the right angled triangle.

• The values of the trigonometric angles are

1. Cos0° =1
2. Sin 45 ° =$\frac{1}{\sqrt{2} }$
3. Sin 90=1
4. Cot 45=1
5. Tan 45=1
6. Cos90=0

• The given equation is solved as

        $cos 0 + sin 90 + {\sqrt{2} } \ sin 45 + cot 45 + tan 45+ cos90$

         $=1+1+ \frac{1}{\sqrt{2} }{\sqrt{2}+1+1+0$

         $=1+1+1+1+1\\=5$

Conclusion:

The value of the equation is 5