find the value of cos (13π/2 - π/6)
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We have cos (13π/2-π/6)
=cos(39π/6-π/6)
=cos(38π/6)
=cos(6π-2π/6)
we know (cos n360-theta)=cos theta
=cos2pi/6
=cos360/6
{putting pi =180}
=cos 60
=1/2
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