Math, asked by balbirsinghknl, 2 months ago

find the value of cos (-1710°)​

Answers

Answered by rkcomp31
1

Answer:

Step-by-step explanation:

\cos (-1750)^\circ\\\\=\cos 1750^\circ\\\\=cos (4\times 360+270)^\circ\\\\=\cos 270^\circ\\\\= -\cos ( 180+90)^\circ\\\\=-\cos 90^\circ\\\\=0

Answered by arivumathis2000
0

Step-by-step explanation:

cos(-x)=cosx

cos(-1710)=cos1710

where 1710=19π/2

cosnπ/2=0,where n is odd

cosnπ/2=1,where n is even

cos(-1710)=0

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