Math, asked by sachutsav74, 1 year ago

Find the value of cos(-1710°).

Answers

Answered by Anonymous
13

= cos(-1710°)

As cos repeats periodically after one complete revolution of 360°.

= cos ( - 1710° + 5*360°)

(it remains Same too).

= cos(-1710° + 1800°)

= cos(90°)

= 0.

Answered by Anonymous
1

\huge{\underline{\underline{\bf{Solution}}}}

\rule{200}{2}

\Large{\underline{\underline{\bf{To \: Find :}}}}

We have to find the value of cos(-1710)°.

\rule{200}{2}

\Large{\underline{\underline{\bf{Explanation :}}}}

We know that Values of cos x repeats after an interval of 2π or 360°.

There will be 5 intervals.

So,

\sf{→Cos(-1710^{\circ})} \\ \\ \sf{→Cos(-1710^{\circ}) + 5 \times 360^{\circ}} \\ \\ \sf{→Cos(-1710^{\circ} + 1800^{\circ})} \\ \\ \sf{→Cos90^{\circ}}

We know that,

\Large{\star{\boxed{\sf{Cos90^{\circ} = 0}}}}

\sf{→0} \\ \\ \sf{\therefore \: Value \: of \: cos(-1710^{\circ}) \: is \: 0}

\Large{\implies{\boxed{\boxed{\sf{Cos(-1710^{\circ}) = 0}}}}}

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