Find the value of cos 2 theta if 2 sin 2theta =root 3
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2Sin 2A = root3 (I have taken A instead of theta)
Sin 2A = root3/2
we know that sin A = root3/2 when2A = 60
=> 2A=60
A=60/2 = 30
Cos 2 A= Cos 2 X 30 = Cos 60
we know cos 60 = 1/2
Hope It Helps :-)
Sin 2A = root3/2
we know that sin A = root3/2 when2A = 60
=> 2A=60
A=60/2 = 30
Cos 2 A= Cos 2 X 30 = Cos 60
we know cos 60 = 1/2
Hope It Helps :-)
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Ф=![\sqrt{3} \sqrt{3}](https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D+)
Ф=![\sqrt{3}/2 \sqrt{3}/2](https://tex.z-dn.net/?f=+%5Csqrt%7B3%7D%2F2)
Ф=1-sin²Ф
⇒1-(√3/2)²
⇒1-![\frac{3}{4} \frac{3}{4}](https://tex.z-dn.net/?f=+%5Cfrac%7B3%7D%7B4%7D+)
⇒![\frac{1}{4} \frac{1}{4}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B4%7D+)
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⇒1-(√3/2)²
⇒1-
⇒
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