Find the value of cos 28 divided by sin 62
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Answered by
19
cos28/sin62
we can write cos 28 as
cos(90°-62)/sin62
=sin62/sin62 [cos(90°-theta)=sin theta]
=1
hence the answer is 1
we can write cos 28 as
cos(90°-62)/sin62
=sin62/sin62 [cos(90°-theta)=sin theta]
=1
hence the answer is 1
Answered by
6
cos28°/sin62°
we write as cos28°
cos(90°-62°)/sin62°
sin62°/sin62°[cos(90°-theta)=sin theta]
=1
we write as cos28°
cos(90°-62°)/sin62°
sin62°/sin62°[cos(90°-theta)=sin theta]
=1
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