Math, asked by erukulatanish, 2 months ago

Find the value of cos 38o x cos 52o − sin 38o x sin 52o​

Answers

Answered by MaheswariS
1

\textbf{Given:}

\mathsf{cos\,38^\circ\;cos\,52^\circ-sin\,38^\circ\;sin\,52^\circ}

\textbf{To find:}

\textsf{The value of}

\mathsf{cos\,38^\circ\;cos\,52^\circ-sin\,38^\circ\;sin\,52^\circ}

\textbf{Solution:}

\textsf{Consider,}

\mathsf{cos\,38^\circ\;cos\,52^\circ-sin\,38^\circ\;sin\,52^\circ}

\textsf{Using the identity,}

\boxed{\mathsf{cos(A+B)=cosA\;cosB-sinA\;sinB}}

\mathsf{=cos(38^\circ+52^\circ)}

\mathsf{=cos\,90^\circ}

\mathsf{=0}

\implies\boxed{\mathsf{cos\,38^\circ\;cos\,52^\circ-sin\,38^\circ\;sin\,52^\circ=0}}

\textbf{Find more:}

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Answered by pulakmath007
4

SOLUTION

TO DETERMINE

The value

cos 38° × cos 52° - sin 38° × sin 52°

FORMULA TO BE IMPLEMENTED

We are aware of the Trigonometric formula that

cos ( 90° - θ ) = sin θ

EVALUATION

cos 38° × cos 52° - sin 38° × sin 52°

= cos ( 90° - 52° ) × cos ( 90° - 38° ) - sin 38° × sin 52°

= sin 52° × sin 38° - sin 38° × sin 52°

= sin 38° × sin 52° - sin 38° × sin 52°

= 0

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