Question

find the value of
cos 47÷Sin 43​

Answer 1

Step-by-step explanation:

(sinA+cosA)(tanA+cosA)−secA−cosec A

(sinA+cosA)(

sinA.cosA

sin

2

A+cos

2

A

)−secA−cosec A

=(

sinA.cosA

sinA+cosA

)−secA−cosec A

=secA+cosec A−secA cosec A

=0

∴ The result is zero (0)

hope it helps plzz mark as brainliest

Answer 2

(sinA+cosA)(tanA+cosA)-secA-cosecA

(sinA+cosA)(sinA.cosA

sin2A+cos2A)-secA-cosecA

=(sinA.cosA

sinA+cosA)-secA-cosecA

=secA+cosecA-secA cosecA=0