Math, asked by haarika78, 1 month ago

find the value of
cos 50°/sin40°+cos49°/sin41°-8sin^2 30°​

Answers

Answered by pc725223gmailcom
1

Answer:

cos 50°/sin40°+cos49°/sin41°-8sin^2 30°

sin(90°-40°)/Sin40°+sin (90°-41°)/sin41°-8×(1/2)^2

Sin40°/sin40°+sin41°/sin41°-8×1/4

1+1-2

2-2

0

Answered by dolusahu498
0

Answer:

cos 50;.sin40+ cos 49 /sin41-8sin ^2 30°

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