find the value of cos 60° geometrically
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hey ..!!
here the ans is...
consider a right angled Δle with A at 60°, BC =1 cm and AB=2 cm
so,∠ BAC=60°
now, cos 60°=BC/AB=1/2
cosec 60°=BC/AB=2/x
by applying pythagores theorem,
AB²=AC²+BC²
2² =x² +1²
4 =x² +1
x² =3
x =√3
hence,
cosec 60°=AB/AC=A2/√3
hope my ans helps u dear..
^-^
plz...make my ans as brainliest if i deserve...
@shuzu
here the ans is...
consider a right angled Δle with A at 60°, BC =1 cm and AB=2 cm
so,∠ BAC=60°
now, cos 60°=BC/AB=1/2
cosec 60°=BC/AB=2/x
by applying pythagores theorem,
AB²=AC²+BC²
2² =x² +1²
4 =x² +1
x² =3
x =√3
hence,
cosec 60°=AB/AC=A2/√3
hope my ans helps u dear..
^-^
plz...make my ans as brainliest if i deserve...
@shuzu
Answered by
3
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