Math, asked by abhayjaiswal2101, 10 months ago

find the value of cos (-870)​

Answers

Answered by mdkumar591
43

please mark brainliest

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Answered by FelisFelis
16

The required value of \cos (-870) is =\frac{\sqrt{3}}{2}.

Step-by-step explanation:

Consider the provided information.

We need to find the value of \cos (-870)

\cos (-870) = \cos 870    (∴cos(-θ)=cosθ)    

=-\cos (900-30)

=-\cos(5\pi-\frac{\pi}{6})

=-\cos(-\frac{\pi}{6})        (∴cos(-θ)=cosθ)  

=\frac{\sqrt{3}}{2}

Hence, the required value of \cos (-870) is =\frac{\sqrt{3}}{2}.

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Prove that sin square A cos square B - cos square A sin square B = sin square A - sin square B

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