Find the value of cos θ cos (90 –θ ) – sin θ sin (90 – θ).
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Trigonometry is the study of the relationship between the sides and angles of a triangle.
Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles.
SOLUTION:
Given:
cos θ cos (90 –θ ) – sin θ sin (90 – θ)
= cos θ sin θ – sin θ cos θ = 0
[ cos (90-θ)] = Sin θ , sin (90-θ)] = cos θ]
cos θ cos (90 –θ ) – sin θ sin (90 – θ) = 0
Hence, the value of cos θ cos (90 –θ ) – sin θ sin (90 – θ) is 0 (zero).
HOPE THIS WILL HELP YOU..
Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles.
SOLUTION:
Given:
cos θ cos (90 –θ ) – sin θ sin (90 – θ)
= cos θ sin θ – sin θ cos θ = 0
[ cos (90-θ)] = Sin θ , sin (90-θ)] = cos θ]
cos θ cos (90 –θ ) – sin θ sin (90 – θ) = 0
Hence, the value of cos θ cos (90 –θ ) – sin θ sin (90 – θ) is 0 (zero).
HOPE THIS WILL HELP YOU..
Answered by
7
it's value is Zero ( 0 ) ....
by using identity of cos(90-x) = sinx and sin(90-x) = cos x
we get , cosx.cos(90-x) - sinx.sin(90-x)
= cosx.sinx - sinx.cosx
= 0
by using identity of cos(90-x) = sinx and sin(90-x) = cos x
we get , cosx.cos(90-x) - sinx.sin(90-x)
= cosx.sinx - sinx.cosx
= 0
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