find the value of cos square 67°-sin square 23°
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Cos² 67° - Sin² 23°
= Cos² (90-23) - Sin² 23°
= Sin² 23° - Sin² 23° [∵ Cos(90-A) = SinA]
= 0
= Cos² (90-23) - Sin² 23°
= Sin² 23° - Sin² 23° [∵ Cos(90-A) = SinA]
= 0
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0
Hey!!!!
We'll use the concept that sin and cos are complementary to each other.
cos²67° - sin²23°
=> cos²67° - cos²(90 - 23)
=> cos²67° - cos²67°
=> 0
Hope this helps
We'll use the concept that sin and cos are complementary to each other.
cos²67° - sin²23°
=> cos²67° - cos²(90 - 23)
=> cos²67° - cos²67°
=> 0
Hope this helps
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