find the value of cos theta if CD equal 3 and bad equal 4
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0
'θ' is in triangle ABD. We need to know AB and AD. Let us find them.
In the △ADC, ∠ADC=90
o
∴AD
2
+DC
2
=AC
2
AD
2
+16
2
=20
2
AD
2
=20
2
−16
2
=400−256=144
∴AD=
144
=12cm
Now, in △ADB, ∠ADB=90
o
AB
2
=AD
2
+BD
2
=12
2
+5
2
=144+25=169
∴AB=
169
=13cm
∴sinθ=
AB
BD
=
13
5
and cosθ=
AB
AD
=
13
12
∴sinθ+cosθ=
13
5
+
13
12
=
13
17
Answered by
0
Answer:
fins to the inbox folder and I will be in the morning sorry
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