Find the value of cos² π/8 + cos² 3π/8 + cos² 5π/8 + cos² 7π/8.
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Answer:-
Cos² (π/8) + Cos² (3π/8) + Cos² (5π/8) + Cos² (7π/8) = 2
Taking L.H.S. -
= Cos² (π/8) + Cos² (3π/8) + Cos² (5π/8) + Cos² (7π/8)
= Cos² (π/8) + Cos² (π/2 - π/8) + Cos² (5π/8) + Cos² (3π/2 + 5π/8)
= Cos² (π/8) + {-Sin (π/8)}² + Cos² (5π/8) + Sin² (5π/8)
= Cos² (π/8) + Sin² (π/8) + Cos² (5π/8) + Sin² (5π/8)
= 1 + 1
= 2.
(R.H.S.)
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