find the value of cos²45+2sin²30
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Answered by
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Answer:
2sin230° – 3cos245° + tan260°
= 2 (1/2)2 – 3(1/root2)2 + (root3)2
= 1/2 – 3/2 + 3
= –2/2 + 3
= –1 + 3
= 2
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2sin230° – 3cos245° + tan260°
= 2 (1/2)2 – 3(1/root2)2 + (root3)2
= 1/2 – 3/2 + 3
= –2/2 + 3
= –1 + 3
= 2
I Hope It Will Help!
^_^
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Answered by
0
Answer:
Step-by-step explanation:cos^2 45 =(1/root2)^2
2sin^30=2(1/2)^2
=> 1/2+1/2=1
hence the required value is 1
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