Question

Find the value of cos27degrees.sin63degrees+cos63degrees

Answer 1

Answer:

As is: not simplifi-able.

Modified (see below): 1.

Step-by-step explanation:

If the question is taken as-is, we get:

$cos27^o.sin63^o + cos63^o$

$= cos27^o.cos27^o + sin27^o$ (since sinA = cos(90 - A) and vice-versa)

$= cos^227^o + sin27^o$

If the question was:

$cos27^o.sin63^o + cos63^o.sin27^o$, then:

$= cos^227^o + sin^227^o$ (following a process similar to the initial solution)

$= 1$ (since $sin^2\theta + cos^2\theta = 1$)