Find the value of Cos35°/Sin55°+Sin12°/Cos78°-Cos18°/sin72°
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Answer:
Cos35°/Sin55°+Sin12°/Cos78°-Cos18°/sin72°= 1
Step-by-step explanation:
sin(90-x)° = cos x°
sin55°=sin(90-35)° = cos 35°
cos35°/sin55° = 1
similarly sin12°=sin(90-78)=cos78°
sin12°/cos78°=1
sin72° = sin(90-18)° = cos18°
cos18°/sin72°=1
Cos35°/Sin55°+Sin12°/Cos78°-Cos18°/sin72°
=1 + 1 - 1
=1
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