Find the value of cos40+cos80+cos160+cos240
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Hello dear user!!! ✌️✌️
Here is your answer goes like this :
=====================================================
Your question :
Find the value of cos40+cos80+cos160+cos240.....
Answer :
cos40°+cos80°+cos160°+cos240°
=2cos(40°+80°)/2cos(40°-80°)/2+cos(180°-20°)+cos(180°+60°)
[∵, cosC+cosD=2cos(C+D)/2cos(C-D)/2]
=2cos60°cos20°+cos{(90°×2)-20°}+cos{(90°×2)+60°}
=2×1/2cos20°+(-cos20°)+(-cos60°)
[∵, cos60°=1/2, cos(180°-A)=-cosA, cos(180°+A)=-cosA]
=cos20°-cos20°-1/2
=-1/2
The answer has been explained......
====================================================
✌️I HOPE THIS WILL HELP YOU ✌️
HAVE A GREAT DAY DEAR ✌️✌️
^_^
Here is your answer goes like this :
=====================================================
Your question :
Find the value of cos40+cos80+cos160+cos240.....
Answer :
cos40°+cos80°+cos160°+cos240°
=2cos(40°+80°)/2cos(40°-80°)/2+cos(180°-20°)+cos(180°+60°)
[∵, cosC+cosD=2cos(C+D)/2cos(C-D)/2]
=2cos60°cos20°+cos{(90°×2)-20°}+cos{(90°×2)+60°}
=2×1/2cos20°+(-cos20°)+(-cos60°)
[∵, cos60°=1/2, cos(180°-A)=-cosA, cos(180°+A)=-cosA]
=cos20°-cos20°-1/2
=-1/2
The answer has been explained......
====================================================
✌️I HOPE THIS WILL HELP YOU ✌️
HAVE A GREAT DAY DEAR ✌️✌️
^_^
Answered by
1
520 is the answer i thank mark me as brainliest
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