Find the value of cos9x × cos4x
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Most times with trigonometric functions, you'll have to apply trigonometric identities to make them work inside of an integral. In this case, we'll be using the trigonometric ID of:
cos(u)*cos(v) = (1/2)*[cos(u-v)+cos(v+u)]
This will give us all we need as we prepare to solve this problem.
Using 9x=u and 4x=v (or vice versa) we apply the ID to obtain the following integral:
∫ (1/2)*[cos(5x)+cos(13x)] dx
From there we can split up the integral into parts, or two separate integrals.
∫ (1/2)*cos(5x) dx + ∫ (1/2)*cos(13x) dx
Now we can do a simplified integral to find our solution (knowing already the integral of a cosine function). We now have our answer:
(1/10)*sin(5x) + (1/13)*sin(13x) + C
Step-by-step explanation:
hope this help you.
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