Question

Find the value of cosec 13pi by 12

Answer 1

Answer:

√6-√2

Step-by-step explanation:

$cosec\frac{13\pi }{12}\\ =cosec(\pi }+\frac{\pi }{12})\\ =-cosec(\frac{\pi }{12} )\\=-cosec(\frac{\pi }{3} -\frac{\pi }{4} )\\=-\frac{1}{sin(\frac{\pi }{3}-\frac{\pi }{4}) }\\=-\frac{1}{sin\frac{\pi }{3}cos\frac{\pi }{4}-cos\frac{\pi }{3} sin\frac{\pi }{4}}\\=-\frac{1}{\frac{\sqrt{3} }{2} *\frac{1}{\sqrt{2} }-\frac{1}{2}*\frac{1}{\sqrt{2}}}\\ =-\frac{2\sqrt{2} }{\sqrt{3}-1 }\\ =- \frac{2\sqrt{2}(\sqrt{3}-1)}{2}\\ =\sqrt{2}(\sqrt{3}-1) \\=\sqrt{6} - \sqrt{2}$

Answer 2

Answer:

This is the answer

Step-by-step explanation:

Hope it will help you