Find the value of (cosec^2 theta -1).tan^2theta
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Answered by
10
Solution: (Cosec^2theta-1).tan^2theta
=(Cot^2theta).tan^2theta
=(P/B)^2×(B/P)^2
=P^2/B^2×B^2/P^2
= 1
=(Cot^2theta).tan^2theta
=(P/B)^2×(B/P)^2
=P^2/B^2×B^2/P^2
= 1
Answered by
7
Answer:
(cosec²∅-1)*(tan²∅)
(cot²∅)*(tan²∅)
(cos²∅/sin²∅)*(sin²∅/cos²∅)
= cos²∅sin²∅/sin²∅cos²∅
= 1
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