Math, asked by TwinkleKhurana, 1 year ago

find the value of cosec² 67' - tan² 23/
Sin²17 + sin² 73
+
sin 59/Cos 31

Answers

Answered by Anonymous

2

Answer:

(cosec²67°- tan²23°)/(sin²17° + sin²73°)

=[cosec²(90°-23°) -tan²23°]/[sin²(90°-73°) +sin²73°]

=(sec²23° - tan²23°)/(cos²73° + sin²73°)

=1/1

=1

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