Question

Find the value of 〖cot〗^(-1)⁡[2 cos (2 〖sin〗^(-1)⁡〖1/2〗 )]​

Answer 1

Answer:    $\frac{\pi }{4}$

Step-by-step explanation:

$cot^{-1} [ 2cos ( 2sin^{-1} (\frac{1}{2} ) ]$

$cot^{-1} [ 2cos ( 2*\frac{\pi }{6}) ]$

$cot^{-1} [ 2cos (\frac{\pi }{3}) ]$

$cot^{-1} [ 2*\frac{1}{2} ]$

$cot^{-1} (1 )$

$\frac{\pi }{4}$