Math, asked by birdlover8071, 1 year ago

Find the value of cot 15°

Answers

Answered by DelcieRiveria
117

Answer:

The value of cot 15° is 2+\sqrt{3}.

Step-by-step explanation:

The given expression is

\cot(15^{\circ})

It can be written as

\cot(15^{\circ})=\cot(45^{\circ})-30^{\circ})

\cot(15^{\circ})=\frac{\cot(45)\cot (30)+1}{\cot(30)-\cot (45)}

\cot(15^{\circ})=\frac{(1)(\sqrt{3})+1}{\sqrt{3}-1}

\cot(15^{\circ})=\frac{\sqrt{3}+1}{\sqrt{3}-1}

Multiply both numerator and denominator by (\sqrt{3}+1).

\cot(15^{\circ})=\frac{\sqrt{3}+1}{\sqrt{3}-1}\times \frac{\sqrt{3}+1}{\sqrt{3}+1}

\cot(15^{\circ})=\frac{(\sqrt{3}+1)^2}{(\sqrt{3})^2-1^2}

\cot(15^{\circ})=\frac{(3+1+2\sqrt{3}}{3-1}

\cot(15^{\circ})=\frac{(2(2+\sqrt{3})}{2}=2+\sqrt{3}

Therefore the value of cot 15° is 2+\sqrt{3}.

Answered by adwaithmohan370
0

Answer:

2+root3

this is the answer i am not able to put root symbol sorry

Similar questions