find the value of :Cot(90–θ )tan θ-(Cosec(90–θ)Secθ / Sin12°Cos15°Sec78°Cosec75° )+ (Cos²(50 + θ) tan² (40 –θ )/ tan15°tan37°tan53°tan75°)
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Mistake in the question.
instead of tan²θ it is cos²θ.
Cot(90–θ )tan θ-(Cosec(90–θ)Secθ / Sin12°Cos15°Sec78°Cosec75° )+ (Cos²(50 + θ) cos² (40 –θ )/ tan15°tan37°tan53°tan75°)
SOLUTION IS IN THE ATTACHMENT
Trigonometry is the study of the relationship between the sides and angles of a triangle.
•Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles.
•An equation involving trigonometry ratios of an angle is called is called a trigonometric identity, if it is true for all values of the angles involved.
•For any acute angle θ, we have 3 identities.
i) sin² θ + cos² θ = 1 ,ii) 1 + tan² θ = sec² θ , iii) cot² θ +1 = cosec² θ.
HOPE THIS WILL HELP YOU....
instead of tan²θ it is cos²θ.
Cot(90–θ )tan θ-(Cosec(90–θ)Secθ / Sin12°Cos15°Sec78°Cosec75° )+ (Cos²(50 + θ) cos² (40 –θ )/ tan15°tan37°tan53°tan75°)
SOLUTION IS IN THE ATTACHMENT
Trigonometry is the study of the relationship between the sides and angles of a triangle.
•Two angles are said to be complementary of their sum is equal to 90° .
θ & (90° - θ) are complementary angles.
•An equation involving trigonometry ratios of an angle is called is called a trigonometric identity, if it is true for all values of the angles involved.
•For any acute angle θ, we have 3 identities.
i) sin² θ + cos² θ = 1 ,ii) 1 + tan² θ = sec² θ , iii) cot² θ +1 = cosec² θ.
HOPE THIS WILL HELP YOU....
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Step-by-step explanation:
cot (90°-theta ) tan theta - cosec (90°-theta) sec theta / sin 12°cos15° sec78° cose 75° + cos^2 (50° + theta ) tan^2 (40°-theta ) /tan 15° tan 37° tan 53° tan 75°
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