find the value of cot inverse of by 17
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cot(17⋅π6)=cot(12π+5π6)=cot(2π+5π6)=cot(5π6)==cot(π−π6)=−cot(π6)=−√3
cot(17⋅π6)=cot(12π+5π6)=cot(2π+5π6)=cot(5π6)==cot(π−π6)=−cot(π6)=−√3
thanush143:
wrong
I also know
we can solve the following problem using tan{A+B}=tanA+tanB/1+tanA.tanB
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