Question

Find the value of cot (tan-1alpha+cot-1alpha
cot(π/)
0​

Answer 1

Answer:

$\cot( \tan^{ - 1} \alpha + \cot ^{ - 1} \alpha )$

$= > \cot( \frac{\pi}{2} )$

$= > \cot( \frac{180^{°} }{2} )$

$= > \cot( {90}^{°} )$

$= > 0$

Step-by-step explanation:

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