Math, asked by hrithiksagar11, 1 year ago

find the value of cot2^a=1÷sin2^a

Answers

Answered by Jahnvi97
5
cot²a = 1÷sin²a
⇒ cot²a × sin²a = 1
⇒ (cos²a/sin²a) × sin²a = 1
⇒ cos²a = 1
⇒ cosa = 1 or -1
⇒ a = 0° and 180°

hrithiksagar11: thankyou
Jahnvi97: your welcome!
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