Question

find the value of cot40/tan50-1/2 cos35/sin55

Answer 1

Given cot40/tan50 - 1/2 cos35/sin55
        = cot(90 -50)/tan50 - 1/2 cos(90 - 55)/sin55
        = tan50/tan50 - 1/2 sin55/sin55
        = 1 - 1/2 (1)
        = 1 - 1/2
        = 1/2
Therefore the value is 1/2.