Find the value of cot40/tan50-sin35/2cos35
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cot40/tan50-sin35/2cos35
cot40/tan(90-50)-sin35/2cos (90-55)
cot40/cot40-sin35/2sin35
=1-1/2
1/2
cot40/tan50-sin35/2cos35 = 1/2
hope its helpful..@.@
vyshnavireddy:
yup
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hiii dear______✌✌✌
cot40/tan50-1/2cos35/sin55
=cot40/cot40-1/2(cos35/sin35)
=1-1/2(1)
=1-1/2=1/2
=1/2
cot40/tan50-1/2cos35/sin55
=cot40/cot40-1/2(cos35/sin35)
=1-1/2(1)
=1-1/2=1/2
=1/2
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