find the value of cot7°cot23°cot60°cot67°cot83°
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Answer:
cot7⁰ = tan 83⁰ ( tan(90-x) = cot(x) )
cot23⁰ = tan67⁰
cot60⁰ = 1/√3
cot7⁰ cot23⁰ cot60⁰ cot67⁰ cot83⁰
= tan83⁰ tan67⁰ (1/√3) cot67⁰ cot83⁰
= (1)(1)(1/√3) ( tanx = 1/cotx)
answer is 1/√3
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