Question

find the value of d^2y/dx^2 when x=0 ​

Answer 1

Answer:

Let function f(x) be y = x^3 + 20x^2

Let function f(x) be y = x^3 + 20x^2To find: d2y/dx2

Let function f(x) be y = x^3 + 20x^2To find: d2y/dx2first find dy/dx

Let function f(x) be y = x^3 + 20x^2To find: d2y/dx2first find dy/dxSo, dy/dx = 3x^2 + 40x

Let function f(x) be y = x^3 + 20x^2To find: d2y/dx2first find dy/dxSo, dy/dx = 3x^2 + 40xFor d2y/dx2 differentiate the dy/dx again

Let function f(x) be y = x^3 + 20x^2To find: d2y/dx2first find dy/dxSo, dy/dx = 3x^2 + 40xFor d2y/dx2 differentiate the dy/dx againd2y/dx2 = d/dx ( 3x^2 + 40x)

= 6x +40

Answer 2

Answer:

anything by zero is equals to undefined so the answer is undefined