Physics, asked by ksrigirirao1970, 9 months ago

find the value of d by dx (2x square)

Answers

Answered by Anonymous

2

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=dy/dx(2x²)

=2X2x

=4x

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Answered by Asterinn

4

$\implies \: \dfrac{d(2 {x}^{2} )}{dx}$

$\implies \: 2 \times \dfrac{d( {x}^{2} )}{dx}$

We know that :-

d(x^n)/dx = n x^(n-1)

Now using Chain rule :-

$\implies \: 2 \times 2x \times\dfrac{d( x )}{dx}$

$\implies \: 2 \times 2x \times1$

$\implies \: 4x$

Answer :

$\implies \: \dfrac{d(2 {x}^{2} )}{dx} = 4x$

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Learn more :-

d(x^n)/dx = n x^(n-1)

d(log x)/dx = 1/x

d(e^x)/dx = e^x

d(sinx)/dx = cosx

d(cos x)/dx = -sin x

d(cosec x)/dx = -cot x cosec x

d(tan x)/dx = sec²x

d(sec x)/dx = secx tanx

d(cot x)/dx = - cosec² x

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