find the value of d/dx (tanx)
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Answer:
sec²x is ur answer here...hope u will get
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Question :- find the value of d/dx (tan x) ?
Solution :-
→ f(x) = (tan x)
using tan x = sin x / cos x ,
→ f'(x) = (sin x / cos x)
using quotient rule now we get,
→ f'(x) = [d/dx (sin x) * cos x - sin x * d/dx( cos x)] / (cos x)²
→ f'(x) = [{cos x * cos x - sin x * (- sin x)}/ cos ²x]
→ f'(x) = (cos² x + sin ² x) / cos²x
using sin²A + cos²A = 1 in numerator,
→ f'(x) = (1/ cos ²x)
using (1/cosA) = sec A ,
→ f'(x) = sec² x (Ans.)
Learn more :-
prove that cosA-sinA+1/cos A+sinA-1=cosecA+cotA
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help me with this trig.
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