Question

find the value of deltaG^* at 25°c for the following eletrochemical cell Cu/Cu^2+(1M)//Ag(1M)/Ag​

Answer 1

Answer:

E_(Cu)^(0)=+0.30V, E_(Ag)^(0)=+0.8V, F=96487C

<br>

E_("cell")=E_(Ag)^(0)-E_(Cu)^(0)=+0.87-0.34=+0.46V

<br>

Ag^(2+)+Cu to Cu^(2+)+2Ag

<br> n=2 <br> Formula

DeltaG^(0)=-n E_("cell")^(0)F

<br>

=2 xx 0.46 xx 96487=-88.768kJ