Question

FIND THE VALUE OF DESCRIMINANT

√2x^2 + 4x + 2√2 = 0

If a = √2 ... B = 4 ... C = 2√2​

Answer 1

Step-by-step explanation:

√2x^3+4x+2√2=0

here a=√2,b=4,c=2√2

discriminant=b^2-4ac

=(4)^2-[4*(√2)*(2√2)]

=16-[4*2(√2)^2]

=16-(4*4)

=0

hence value of discriminant is zero.

Answer 2

Answer:

D = 0

Step-by-step explanation:

Given Quadratic equation → √2x² + 4x + 2√2 = 0

Compare with general form of quadratic equation i.e. ax²+bx+c=0, we identify that:

• a = √2
• b = 4
• c = 2√2

Finding Discriminant:

D = b² - 4ac

➩ D = (4)² - 4 (√2) (2√2)

➟ D = 16 - 8 (√2)²

☞ D = 16 - 8 (2)

➝ D = 16 - 16

↦ D = 0

∴ The Discriminant of the Quadratic equation = 0

This means that roots are real and equal.