Question

find the value of disciminant of equation and determine the nature of roots 3ysquare+9y+4=0​

Answer 1

3y²+9y+4=0

So, the discriminant is

$Δ = (\prod _{i < j \leq n} \: (x _j- x_i) ) ^{2} \\ Δ = b^{2} - 4ac$

Therefore, the discriminant is

Δ = (9)²−4(3)(4) = 81 − 48 = 33

As, Discriminant[3y²+9y+4,y] > 0

$\implies x _{1,2} \in ℝ : x_{1} ≠ x_{2}$

Answer 2

Step-by-step explanation:

3y^2+9y+4=0

discriminant,

b^2-4ac=(9)^2-4.3.4

=81-48

=33>0

therefore,the roots are real and unequal.