Question

find the value of discreaminant (∆)for the quadratic equations x²-6x-5=0​

Answer 1

☯ GIVEN :

• $\bf{x^2 -6x-5 = 0}$

☯TO FIND :

• The value of Discriminant.

☯ FORMULA REQUIRED :

• $\bigstar{\underline{\boxed {\red{\bf{D= b^2 -4ac}}}}}$

➲SOLUTION :

✞ We have,

• a = 1

• b = -6

• c = -5

Substituting the given values in the formula :

$\mapsto {\tt{D= b^2 - 4ac}}$

$\mapsto {\tt{D= ( - 6)^2 - 4\times 1\times (-5)}}$

$\mapsto{\tt{D=36+20}}$

$\leadsto\underline{ \huge{\pink{\boxed{ \bf{D =56}}}}}$

$\huge{ \purple{\therefore}}$ Here, D is greater than 0, so roots are real and distinct..