Question

find the value of discriminant 0f the QE2x2-5x-1=0and nature of the root​

Answer 1

Step-by-step explanation:

Given equation is 2x2−5x+1=0

On comparing with ax2+bx+c=0 we get

a=2,b=−5 and c=1

D=b2−4ac

=(−5)2−4×2×1=5−8

∴ Discriminant =−3<0 

Since, discriminant is negative ∴ quadratic equation 2x2−5x+1=0 has no real roots . i.e, imaginary roots.

Answer 2

Answer:

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Step-by-step explanation:

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