Find the Value of discriminant.
√2
2
+ 4 + 2√2 = 0
Comparing with 2
+ + = 0
∴ = ___________ , b = _________ , C = __________
2 − 4 = (4)
2 − 4 × _________ × ________
= 16 − _______
= ______
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Answer:
2+4+2√2 =0
comparing with standard from ax^2+bx+c= 0
a =2 ,b =4 ,c =2
using formula, Δ = b^2 √4-ac
4^2 = √ 4-2*2
16 = 4 - 4
16 = 0
16 is the value of discrimination........
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