Find the value of discriminant 2y²-5y+10=0
Answers
Answered by
3
Answer:
-55
Step-by-step explanation:
2y2 - 5y + 10 = 0
ax2 + bx + c = 0
a=2 b = -5 , c=10
b2 - 4ac
-(5)2 -4×2×10
=25-8
therefore = -55
Answered by
9
Answer:
2y²-5y +10=0 comparing the given equation with ax² + bx +c=0
a=2 ,b= -5 And c= 10 so,the discriminant
b² - 4ac = (-5)²-4×2×10 = 25-80= -55
Step-by-step explanation:
I hope its helpful for u
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