Math, asked by kripashankars191, 6 hours ago

Find the value of discriminant 2y²-5y+10=0

Answers

Answered by reethuamin
3

Answer:

-55

Step-by-step explanation:

2y2 - 5y + 10 = 0

ax2 + bx + c = 0

a=2 b = -5 , c=10

b2 - 4ac

-(5)2 -4×2×10

=25-8

therefore = -55

Answered by palakyadav760
9

Answer:

2y²-5y +10=0 comparing the given equation with ax² + bx +c=0

a=2 ,b= -5 And c= 10 so,the discriminant

b² - 4ac = (-5)²-4×2×10 = 25-80= -55

Step-by-step explanation:

I hope its helpful for u

Similar questions