Find the value of discriminant 5x2 + 6x + 11 = 0
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Answer :-
Given :-
- Equation → 5x² + 6x + 11 = 0
To Find :-
- Discriminant
Solution :-
We know that,
Discriminant = b² - 4ac
For the given equation :-
- a = 5
- b = 6
- c = 11
→ D = 6² - 4 × 5 × 11
→ D = 36 - 20 × 11
→ D = 36 - 220
→ D = -184
Value of Discriminant = -184
Additional information :-
Nature of roots :-
1. If D > 0 then roots are real and different.
2. If D is a perfect square, then roots are rational and different.
3. If D = 0, then roots are real and equal
4. If D < 0 then, roots are imaginary and unequal or complex conjugate.
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